[R-br] [Dúvida] Combinar expression e paste.
Pedro Rafael
pedro.rafael.marinho em gmail.com
Quinta Maio 23 22:58:23 BRT 2013
Legal suas dicas Benilton. Obrigado pela força. Vou dar uma pesquisada de
como resolver esse problema.
[ ],
Pedro Rafael Diniz Marinho.
Em 21 de maio de 2013 23:47, beniltoncarvalho [via R-br] <
ml-node+s2285057n4659387h74 em n4.nabble.com> escreveu:
> na real, vc vai querer procurar como fazer uma tabela no canto
> superior direito (acho q o demo(plotmath) serve de exemplo)...
>
> uma solucao relativamente simples (mas q vc pode nao achar "legal"
> esteticamente) e' fazer "zero padding"...
>
> black2=black3=c(10.03,1,2)
> red2=red3 =c(1.3,100.1,2)
> blue3 =blue2=c(1,10.02,2)
> orange3=orange2=c(4,4,10.1)
>
> makeExp <- function(L, a, b)
> eval(substitute(expression(paste(lambda==L," , ", "a"==a, ", b"==b)),
> list(L=sprintf('%06.2f', L),
> a=sprintf('%06.2f', a),
> b=sprintf('%06.2f', b))))
>
> plot(1)
> legend("topright", legend =
> c(makeExp(black3, black2[1], black2[2]),
> makeExp(red3, red2[1], red2[2]),
> makeExp(blue3, blue2[1], blue2[2]),
> makeExp(orange3, orange2[1], orange2[2])),
> bty="n", lty=c(1,1,1,1), lwd=c(2,2,2,2),
> col=c("black", "red", "darkblue", "orange"))
>
> Em 21 de maio de 2013 23:21, Pedro Rafael
> <[hidden email] <http://user/SendEmail.jtp?type=node&node=4659387&i=0>>
> escreveu:
>
> > Com essa gambiarra acho que roda.
> >
> > rm(list=ls(all=TRUE))
> > black2 = black3=c(10.03,1,2)
> > red2 = red3 =c(1.3,100.1,2)
> > blue3 =blue2 = c(1,10.02,2)
> > orange3 = orange2 = c(4,4,10.1)
> >
> >
> > plot(1)
> > legend("topright", legend =
> >
> > c(eval(substitute(expression(paste(lambda==L," , ", "a"==a, ",
> > b"==b)), list(L = black3, a = black2[1], b=black2[2]))),
> >
> > eval(substitute(expression(paste(lambda==L," , ", "a"==a, ",
> > b"==b)), list(L = red3, a = red2[1], b=red2[2]))),
> >
> > eval(substitute(expression(paste(lambda==L," , ", "a"==a, ",
> > b"==b)), list(L = blue3, a = blue2[1], b=blue2[2]))),
> >
> > eval(substitute(expression(paste(lambda==L," , ", "a"==a, ",
> > b"==b)), list(L = orange3, a = orange2[1], b=orange2[2])))),
> > bty="n", lty = c(1,1,1,1), col = c("black", "red", "darkblue",
> > "orange"), lwd=c(2,2,2,2))
> >
> >
> >
> > [ ],
> > Pedro Rafael Diniz Marinho.
> >
> >
> > Em 21 de maio de 2013 23:16, beniltoncarvalho [via R-br]
> > <[hidden email] <http://user/SendEmail.jtp?type=node&node=4659387&i=1>>
> escreveu:
> >>
> >> exemplo nao reproduzivel... experimente abrir uma sessao nova do R,
> >> copiar e colar....
> >>
> >> Em 21 de maio de 2013 23:10, Pedro Rafael
> >> <[hidden email]> escreveu:
> >>
> >> > Veja esse exemplo:
> >> >
> >> > black=c(10.03,1,2)
> >> > plot(1)
> >> >
> >> > legend("topright", legend =
> >> >
> >> > c(eval(substitute(expression(paste(lambda==L," , ", "a"==a,
> ",
> >> > b"==b)), list(L = black3, a = black2[1], b=black2[2]))),
> >> >
> >> > eval(substitute(expression(paste(lambda==L," , ", "a"==a,
> ",
> >> > b"==b)), list(L = red3, a = red2[1], b=red2[2]))),
> >> >
> >> > eval(substitute(expression(paste(lambda==L," , ", "a"==a,
> ",
> >> > b"==b)), list(L = blue3, a = blue2[1], b=blue2[2]))),
> >> >
> >> > eval(substitute(expression(paste(lambda==L," , ", "a"==a,
> ",
> >> > b"==b)), list(L = orange3, a = orange2[1], b=orange2[2])))),
> >> > bty="n", lty = c(1,1,1,1), col = c("black", "red", "darkblue",
> >> > "orange"), lwd=c(2,2,2,2))
> >> >
> >> > Observe que os números tem quantidades de dígitos diferentes, umas
> >> > linhas
> >> > ficando maiores e outras menores. Não teria como "justificar" essas
> >> > legendas? Não sei se fui claro...
> >> >
> >> > Obrigado pela ajuda.
> >> >
> >> > [ ],
> >> > Pedro Rafael Diniz Marinho.
> >> >
> >> >
> >> > Em 21 de maio de 2013 22:33, beniltoncarvalho [via R-br]
> >> > <[hidden email]> escreveu:
> >> >>
> >> >> "alinhar" com respeito a q?
> >> >>
> >> >> plot(1)
> >> >> ## alinhado no canto inferior direito
> >> >> legend('bottomright', legend=substitute(beta==val, list(val=beta1)))
> >> >> ## alinhado no canto inferior esquerdo
> >> >> legend('bottomleft', legend=substitute(beta==val, list(val=beta1)))
> >> >> ## alinhado no canto superior direito
> >> >> legend('topright', legend=substitute(beta==val, list(val=beta1)))
> >> >> ## alinhado no canto superior esquerdo
> >> >> legend('topleft', legend=substitute(beta==val, list(val=beta1)))
> >> >> ## alinhado no centro
> >> >> legend('center', legend=substitute(beta==val, list(val=beta1)))
> >> >> ## alinhado no topo
> >> >> legend('top', legend=substitute(beta==val, list(val=beta1)))
> >> >> ## alinhado na base
> >> >> legend('bottom', legend=substitute(beta==val, list(val=beta1)))
> >> >> ## alinhado na direita
> >> >> legend('right', legend=substitute(beta==val, list(val=beta1)))
> >> >> ## alinhado na esquerda
> >> >> legend('left', legend=substitute(beta==val, list(val=beta1)))
> >> >>
> >> >>
> >> >> Em 21 de maio de 2013 22:07, Pedro Rafael
> >> >> <[hidden email]> escreveu:
> >> >>
> >> >> > Existe alguma forma de alinhar a legenda?
> >> >> >
> >> >> > [ ],
> >> >> > Pedro Rafael Diniz Marinho.
> >> >> >
> >> >> >
> >> >> > Em 17 de maio de 2013 01:13, Pedro Rafael <[hidden email]>
> >> >> > escreveu:
> >> >> >
> >> >> >> Muito obrigado a todos. Obrigado André.
> >> >> >>
> >> >> >> Robert, muito interessante sua solução. Em geral qual a utilidade
> do
> >> >> >> comando substitute? Ele ajuda além dessa situações à resolver que
> >> >> >> tipo
> >> >> >> de
> >> >> >> problemas?
> >> >> >>
> >> >> >> Obrigado.
> >> >> >>
> >> >> >> [ ],
> >> >> >> Pedro Rafael Diniz Marinho.
> >> >> >>
> >> >> >>
> >> >> >> Em 17 de maio de 2013 00:52, Robert Iquiapaza [via R-br]
> >> >> >> <[hidden email]> escreveu:
> >> >> >>
> >> >> >>> Pode usar
> >> >> >>>
> >> >> >>> beta1=10
> >> >> >>>
> >> >> >>>
> >> >> >>>
> >> >> >>>
> >> >> >>>
> legend("topright",eval(substitute(expression(paste(beta==A)),list(A=beta1))))
>
> >> >> >>>
> >> >> >>> Sds
> >> >> >>>
> >> >> >>> From: [hidden email]
> >> >> >>> Sent: Friday, May 17, 2013 12:06 AM
> >> >> >>> To: [hidden email]
> >> >> >>> Subject: Re: [R-br][Dúvida] Combinar expression e paste.
> >> >> >>>
> >> >> >>> Olá André. O problema é que o beta foi chamado em linha
> diferente.
> >> >> >>> Minha
> >> >> >>> dúvida é como jogar o valor da variável beta na primeira linha
> da
> >> >> >>> legenda
> >> >> >>> que fique (a = 10). O beta que você chamou estava fora do
> >> >> >>> expression.
> >> >> >>> Ou
> >> >> >>> seja, estava em linha diferente do beta =.
> >> >> >>>
> >> >> >>> Gostaria de uma legenda do tipo:
> >> >> >>>
> >> >> >>> beta = 10.
> >> >> >>>
> >> >> >>> [ ],
> >> >> >>> Pedro Rafael Diniz Marinho.
> >> >> >>>
> >> >> >>>
> >> >> >>> Em 16 de maio de 2013 23:53, andrebvs [via R-br] <[hidden
> email]>
> >> >> >>> escreveu:
> >> >> >>>
> >> >> >>>>
> >> >> >>>> Olá Pedro, acho que é isso,
> >> >> >>>>
> >> >> >>>> beta = 10
> >> >> >>>> plot(1:5, 1:5,type="n",main="Expressões
> >> >> >>>> Matemáticas",xlab="",ylab="")
> >> >> >>>> legend("topright",legend = c(expression(beta, paste("a =
> >> >> >>>> ")),beta))
> >> >> >>>>
> >> >> >>>> Att.
> >> >> >>>> André BVS
> >> >> >>>>
> >> >> >>>> ________________________________
> >> >> >>>> Em 16/05/2013 23:36, Pedro Rafael < [hidden email] > escreveu:
> >> >> >>>> Pessoal estou fazendo alguns gráficos e estou combinando os
> >> >> >>>> comandos
> >> >> >>>> expression e paste. O problema é que quando chamo o comando
> paste
> >> >> >>>> dentro do
> >> >> >>>> comando expression só estou conseguindo colocar os valores
> >> >> >>>> numéricos
> >> >> >>>> das
> >> >> >>>> variáveis digitando esses valores.
> >> >> >>>> Por exemplo:
> >> >> >>>>
> >> >> >>>> beta = 10
> >> >> >>>> legend("topright", legend = c(expression(beta, paste(" a=
> 10")))
> >> >> >>>>
> >> >> >>>> Se eu fizer legend("topright", legend = c(expression(beta,
> >> >> >>>> paste(" =
> >> >> >>>> ",
> >> >> >>>> beta))) o valor 10 da variável beta não é substituído.
> >> >> >>>> Gostaria de alguma forma de não precisar digitar uma informação
> >> >> >>>> que
> >> >> >>>> já
> >> >> >>>> tenho em uma variável.
> >> >> >>>>
> >> >> >>>>
> >> >> >>>>
> >> >> >>>> [ ],
> >> >> >>>> Pedro Rafael Diniz Marinho.
> >> >> >>>>
> >> >> >>>>
> >> >> >>>> _______________________________________________
> >> >> >>>> R-br mailing list
> >> >> >>>> [hidden email]
> >> >> >>>> https://listas.inf.ufpr.br/cgi-bin/mailman/listinfo/r-br
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> >> >> >>>> forneça
> >> >> >>>> código mínimo reproduzível.
> >> >> >>>>
> >> >> >>>> ________________________________
> >> >> >>>> If you reply to this email, your message will be added to the
> >> >> >>>> discussion
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> >> >> >>>>
> >> >> >>>>
> >> >> >>>>
> >> >> >>>>
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> >> >> >>>> NAML
> >> >> >>>
> >> >> >>>
> >> >> >>>
> >> >> >>> ________________________________
> >> >> >>> _______________________________________________
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> >> >> >>>
> >> >> >>>
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> >> >> >>>
> >> >> >>> ________________________________
> >> >> >>> If you reply to this email, your message will be added to the
> >> >> >>> discussion
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> >> >> >>>
> >> >> >>>
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> >> >> >>> NAML
> >> >> >>
> >> >> >>
> >> >> >
> >> >> >
> >> >> > _______________________________________________
> >> >> > R-br mailing list
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> forneça
> >> >> > código
> >> >> > mínimo reproduzível.
> >> >> _______________________________________________
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> >> >> código mínimo reproduzível.
> >> >>
> >> >>
> >> >> ________________________________
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> >> >> discussion
> >> >> below:
> >> >>
> >> >>
> >> >>
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> >> >> To unsubscribe from R-br, click here.
> >> >> NAML
> >> >
> >> >
> >> >
> >> > _______________________________________________
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> >> > mínimo reproduzível.
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> >>
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> >> NAML
> >
> >
> >
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